What is 5x^2+5y^2-36x+98y-1=0 ?

The solution to 5x^2+5y^2-36x+98y-1=0 is Circle with (a,b)=(18/5 ,-49/5),r=sqrt(546/5)

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5x^2+5y^2-36x+98y-1=0

5 x^{2} + 5 y^{2} - 36 x + 98 y - 1 = 0

(a, b) = (\frac{18}{5}, - \frac{49}{5}), r = \frac{546}{5}

Solution steps

5 x^{2} + 5 y^{2} - 36 x + 98 y - 1 = 0

Rewrite

5 x^{2} + 5 y^{2} - 36 x + 98 y - 1 = 0

in the form of the standard circle equation

(x - \frac{18}{5})^{2} + (y - (- \frac{49}{5}))^{2} = (\frac{546}{5})^{2}

Therefore the circle properties are:

(a, b) = (\frac{18}{5}, - \frac{49}{5}), r = \frac{546}{5}

(x - 5)^{2} + (y - 2)^{2} = 1

x, x^{2} + 400 x + p (x)^{2} + 250 p = 60000

x^{2} + y^{2} - 18 x - 9 = 0

- x^{2} - y^{2} + 4 x = 0

(x - 4)^{2} + y^{2} = 5^{2}

What is 5x^2+5y^2-36x+98y-1=0 ?
The solution to 5x^2+5y^2-36x+98y-1=0 is Circle with (a,b)=(18/5 ,-49/5),r=sqrt(546/5)