What is 4x^{(2)}+4y^{(2)}-56x+8y+56=0 ?

The solution to 4x^{(2)}+4y^{(2)}-56x+8y+56=0 is Circle with (a,b)=(7,-1),r=6

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4x^{(2)}+4y^{(2)}-56x+8y+56=0

4 x^{(2)} + 4 y^{(2)} - 56 x + 8 y + 56 = 0

(a, b) = (7, - 1), r = 6

Solution steps

4 x^{2} + 4 y^{2} - 56 x + 8 y + 56 = 0

Rewrite

4 x^{2} + 4 y^{2} - 56 x + 8 y + 56 = 0

in the form of the standard circle equation

(x - 7)^{2} + (y - (- 1))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (7, - 1), r = 6

100 - 25 x^{2} - 25 y^{2} = 0

(x + 8)^{2} + (y + 2)^{2} = 36

x^{2} - 2 x + y^{2} - 8 = 0

x^{2} - 14 x + y^{2} + 2 y + 50 = 4

x^{2} + y^{2} + 6 x - 47 = 387

What is 4x^{(2)}+4y^{(2)}-56x+8y+56=0 ?
The solution to 4x^{(2)}+4y^{(2)}-56x+8y+56=0 is Circle with (a,b)=(7,-1),r=6