What is x^2+y^2-6x-4y=0 ?

The solution to x^2+y^2-6x-4y=0 is Circle with (a,b)=(3,2),r=sqrt(13)

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x^2+y^2-6x-4y=0

x^{2} + y^{2} - 6 x - 4 y = 0

(a, b) = (3, 2), r = 13

Solution steps

x^{2} + y^{2} - 6 x - 4 y = 0

Rewrite

x^{2} + y^{2} - 6 x - 4 y = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 2)^{2} = (13)^{2}

Therefore the circle properties are:

(a, b) = (3, 2), r = 13

4 x^{2} + 4 y^{2} - 16 y + 15 = 0

2 x^{2} + 8 x + 2 y^{2} - 18 y = - \frac{33}{2}

x^{2} + 4 x + y^{2} - 14 y = - 3

(x - 1)^{2} + (y + 2)^{2} + (x - 4)^{2} + (y - 6)^{2} = 73

x^{2} + y^{2} + 28 x - 32 y + 448 = 0

What is x^2+y^2-6x-4y=0 ?
The solution to x^2+y^2-6x-4y=0 is Circle with (a,b)=(3,2),r=sqrt(13)