What is x^2+6x+y^2=16y-68 ?

The solution to x^2+6x+y^2=16y-68 is Circle with (a,b)=(-3,8),r=sqrt(5)

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x^2+6x+y^2=16y-68

x^{2} + 6 x + y^{2} = 16 y - 68

(a, b) = (- 3, 8), r = 5

Solution steps

x^{2} + 6 x + y^{2} = 16 y - 68

Rewrite

x^{2} + 6 x + y^{2} = 16 y - 68

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 8)^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 8), r = 5

x^{2} + y^{2} + 2 x + \frac{10}{3} y - 16 = 0

17 = (x - 1)^{2} + (y + 1)^{2}

(x - 8)^{2} + (y + 3)^{2} = 91

x^{2} + y^{2} - 12 x - 10 y - 15 = 0

\frac{3}{2} x^{2} + \frac{3}{2} y^{2} = \frac{75}{2}

What is x^2+6x+y^2=16y-68 ?
The solution to x^2+6x+y^2=16y-68 is Circle with (a,b)=(-3,8),r=sqrt(5)