What is 4x+2y=x^2+y^2 ?

The solution to 4x+2y=x^2+y^2 is Circle with (a,b)=(2,1),r=sqrt(5)

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4x+2y=x^2+y^2

4 x + 2 y = x^{2} + y^{2}

(a, b) = (2, 1), r = 5

Solution steps

4 x + 2 y = x^{2} + y^{2}

Rewrite

4 x + 2 y = x^{2} + y^{2}

in the form of the standard circle equation

(x - 2)^{2} + (y - 1)^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (2, 1), r = 5

y^{(2)} + x^{(2)} - 4 x - 5 = 0

x^{2} + y^{2} = 3 x - y

3 x^{2} + 3 y^{2} - 12 x - 24 y - 48 = 0

x^{2} + y^{2} - 8 x + 4 y - 10 = 0

x^{(2)} + y^{(2)} + 8 x - 6 y = 6

What is 4x+2y=x^2+y^2 ?
The solution to 4x+2y=x^2+y^2 is Circle with (a,b)=(2,1),r=sqrt(5)