What is x^2+y^2+9x+10=0 ?

The solution to x^2+y^2+9x+10=0 is Circle with (a,b)=(-9/2 ,0),r=(sqrt(41))/2

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x^2+y^2+9x+10=0

x^{2} + y^{2} + 9 x + 10 = 0

(a, b) = (- \frac{9}{2}, 0), r = \frac{41}{2}

Solution steps

x^{2} + y^{2} + 9 x + 10 = 0

Rewrite

x^{2} + y^{2} + 9 x + 10 = 0

in the form of the standard circle equation

(x - (- \frac{9}{2}))^{2} + (y - 0)^{2} = (\frac{41}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{9}{2}, 0), r = \frac{41}{2}

4 y^{2} - 72 y = 316 - 4 x^{2} - 24 x

(x - \frac{1}{2})^{2} + (y + \frac{1}{4})^{2} = 12

x^{(2)} + y^{(2)} + 4 x - 10 y = - 16

y^{2} = \frac{- 3 x ^{2} + 1}{3}

4 x^{2} + 4 x + 4 y^{2} - 24 y - 27 = 0

What is x^2+y^2+9x+10=0 ?
The solution to x^2+y^2+9x+10=0 is Circle with (a,b)=(-9/2 ,0),r=(sqrt(41))/2