What is x^2+y^2+14x+8y+3=0 ?

The solution to x^2+y^2+14x+8y+3=0 is Circle with (a,b)=(-7,-4),r=sqrt(62)

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x^2+y^2+14x+8y+3=0

x^{2} + y^{2} + 14 x + 8 y + 3 = 0

(a, b) = (- 7, - 4), r = 62

Solution steps

x^{2} + y^{2} + 14 x + 8 y + 3 = 0

Rewrite

x^{2} + y^{2} + 14 x + 8 y + 3 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - (- 4))^{2} = (62)^{2}

Therefore the circle properties are:

(a, b) = (- 7, - 4), r = 62

x^{2} + y^{2} + 18 x - 30 y + 297 = 0

(x + 3)^{2} + (y - 9)^{2} = 21

5 x^{2} + 5 y^{2} + 10 x - y = 10

x^{2} + (y - 1)^{2} - 5 \leq 0

(x + 3)^{2} + (y + 5)^{2} = 5

What is x^2+y^2+14x+8y+3=0 ?
The solution to x^2+y^2+14x+8y+3=0 is Circle with (a,b)=(-7,-4),r=sqrt(62)