What is x^2+(y+6)^2= 3/4 ?

The solution to x^2+(y+6)^2= 3/4 is Circle with (a,b)=(0,-6),r=sqrt(3/4)

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x^2+(y+6)^2= 3/4

x^{2} + (y + 6)^{2} = \frac{3}{4}

(a, b) = (0, - 6), r = \frac{3}{4}

Solution steps

x^{2} + (y + 6)^{2} = \frac{3}{4}

Rewrite

x^{2} + (y + 6)^{2} = \frac{3}{4}

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 6))^{2} = (\frac{3}{4})^{2}

Therefore the circle properties are:

(a, b) = (0, - 6), r = \frac{3}{4}

x^{2} + y^{2} - 12 x + 2 y = - 21

x^{2} + 4 x + y^{2} + 4 = 9 ((x - 2)^{2} + (y + 4)^{2})

x^{2} - 6 + y^{2} = 81

x^{2} + (y + 1)^{2} - 4 = 0

(x - \frac{33}{4})^{2} + y^{2} = 25

What is x^2+(y+6)^2= 3/4 ?
The solution to x^2+(y+6)^2= 3/4 is Circle with (a,b)=(0,-6),r=sqrt(3/4)