What is (x-8)^2+(y-0)^2=sqrt(5)^2 ?

The solution to (x-8)^2+(y-0)^2=sqrt(5)^2 is Circle with (a,b)=(8,0),r=sqrt((\sqrt{5))^2}

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(x-8)^2+(y-0)^2=sqrt(5)^2

(x - 8)^{2} + (y - 0)^{2} = 5^{2}

(a, b) = (8, 0), r = (5)^{2}

Solution steps

(x - 8)^{2} + (y - 0)^{2} = (5)^{2}

Rewrite

(x - 8)^{2} + (y - 0)^{2} = 5^{2}

in the form of the standard circle equation

(x - 8)^{2} + (y - 0)^{2} = ((5)^{2})^{2}

Therefore the circle properties are:

(a, b) = (8, 0), r = (5)^{2}

x^{2} + y^{2} = 15 + 14 x

(x + 1)^{2} + (y - 1)^{2} = 61

x^{2} + y^{2} + 6 x + 22 y + 114 = 0

x^{2} - 10 x + y^{2} - 6 y + 5 = 0

x^{2} + y^{2} - 16 x + 2 y - 20 = 0

What is (x-8)^2+(y-0)^2=sqrt(5)^2 ?
The solution to (x-8)^2+(y-0)^2=sqrt(5)^2 is Circle with (a,b)=(8,0),r=sqrt((\sqrt{5))^2}