What is (x+0)^2+(y+0)^2=3^2 ?

The solution to (x+0)^2+(y+0)^2=3^2 is Circle with (a,b)=(0,0),r=3

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(x+0)^2+(y+0)^2=3^2

(x + 0)^{2} + (y + 0)^{2} = 3^{2}

(a, b) = (0, 0), r = 3

Solution steps

(x + 0)^{2} + (y + 0)^{2} = 3^{2}

Rewrite

(x + 0)^{2} + (y + 0)^{2} = 3^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 3

(X - 5)^{2} + (y - 4)^{2} = 25

(x + 5)^{2} + (y + 5)^{2} = 64

x^{2} + y^{2} - 8 x - 6 y = - 9

x^{2} + y^{2} + 4 x + 28 y = 175

4 x^{2} + 4 y^{2} - 16 x + 24 y - 51 = 0

What is (x+0)^2+(y+0)^2=3^2 ?
The solution to (x+0)^2+(y+0)^2=3^2 is Circle with (a,b)=(0,0),r=3