What is x^2+y^2+10x-2y-23=0 ?

The solution to x^2+y^2+10x-2y-23=0 is Circle with (a,b)=(-5,1),r=7

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x^2+y^2+10x-2y-23=0

x^{2} + y^{2} + 10 x - 2 y - 23 = 0

(a, b) = (- 5, 1), r = 7

Solution steps

x^{2} + y^{2} + 10 x - 2 y - 23 = 0

Rewrite

x^{2} + y^{2} + 10 x - 2 y - 23 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 1)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 5, 1), r = 7

(x - 6)^{2} + (y - 3)^{2} = 20^{2}

(x - 13)^{2} + (y + 7)^{2} = 144

x^{2} + (y - \frac{1}{4})^{2} = \frac{16}{9}

3 x^{2} + 3 y^{2} - 30 x + 36 y - 9 = 0

x^{2} + y^{2} + 2 x + 16 y + 61 = 0

What is x^2+y^2+10x-2y-23=0 ?
The solution to x^2+y^2+10x-2y-23=0 is Circle with (a,b)=(-5,1),r=7