What is x^2+y^2+6x+16y-8=0 ?

The solution to x^2+y^2+6x+16y-8=0 is Circle with (a,b)=(-3,-8),r=9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2+6x+16y-8=0

x^{2} + y^{2} + 6 x + 16 y - 8 = 0

(a, b) = (- 3, - 8), r = 9

Solution steps

x^{2} + y^{2} + 6 x + 16 y - 8 = 0

Rewrite

x^{2} + y^{2} + 6 x + 16 y - 8 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 8))^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 8), r = 9

4 x^{2} + 4 y^{2} + 8 x - 4 y - 3 = 0

(x - \frac{1}{2 ( \frac{3}{2} )})^{2} + y^{2} = (\frac{1}{2 ( \frac{3}{2} )})^{2}

x^{2} + y^{2} - 25 x = - 1 - 3 y

(x - 11)^{2} + (y - 8)^{2} = 268

4 x^{2} - 24 x + 4 y^{2} + 20 y = 39

What is x^2+y^2+6x+16y-8=0 ?
The solution to x^2+y^2+6x+16y-8=0 is Circle with (a,b)=(-3,-8),r=9