What is x^2+y^2+5=2x+8y+10 ?

The solution to x^2+y^2+5=2x+8y+10 is Circle with (a,b)=(1,4),r=sqrt(22)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2+5=2x+8y+10

x^{2} + y^{2} + 5 = 2 x + 8 y + 10

(a, b) = (1, 4), r = 22

Solution steps

x^{2} + y^{2} + 5 = 2 x + 8 y + 10

Rewrite

x^{2} + y^{2} + 5 = 2 x + 8 y + 10

in the form of the standard circle equation

(x - 1)^{2} + (y - 4)^{2} = (22)^{2}

Therefore the circle properties are:

(a, b) = (1, 4), r = 22

(2 + y)^{2} + (2 + x)^{2} = 6^{2}

x^{2} + (y + 1)^{2} = 10

x^{2} + (y + 1)^{2} = 11

(x - 3)^{2} + (y - 5)^{2} + (x + 4)^{2} + (y - 2)^{2} = 30

x^{2} + y^{2} - 5 y - 4 y = 46

What is x^2+y^2+5=2x+8y+10 ?
The solution to x^2+y^2+5=2x+8y+10 is Circle with (a,b)=(1,4),r=sqrt(22)