What is x^2+y^2-6x-4y-18=0 ?

The solution to x^2+y^2-6x-4y-18=0 is Circle with (a,b)=(3,2),r=sqrt(31)

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x^2+y^2-6x-4y-18=0

x^{2} + y^{2} - 6 x - 4 y - 18 = 0

(a, b) = (3, 2), r = 31

Solution steps

x^{2} + y^{2} - 6 x - 4 y - 18 = 0

Rewrite

x^{2} + y^{2} - 6 x - 4 y - 18 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 2)^{2} = (31)^{2}

Therefore the circle properties are:

(a, b) = (3, 2), r = 31

x^{2} + y^{2} + 2 x - 12 y + 12 = 0

x (x - 5) + (y - 2)^{2} = 0

(x - 3)^{2} + (y - 4)^{2} - 9 = 0

8 = x^{2} + x + y^{2} - y + 1

3^{2} = (x - 2)^{2} + (y - 4)^{2}

What is x^2+y^2-6x-4y-18=0 ?
The solution to x^2+y^2-6x-4y-18=0 is Circle with (a,b)=(3,2),r=sqrt(31)