What is x^2+y^2+10x+6y+18=0x ?

The solution to x^2+y^2+10x+6y+18=0x is Circle with (a,b)=(-5,-3),r=4

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x^2+y^2+10x+6y+18=0x

x^{2} + y^{2} + 10 x + 6 y + 18 = 0 x

(a, b) = (- 5, - 3), r = 4

Solution steps

x^{2} + y^{2} + 10 x + 6 y + 18 = 0 \cdot x

Rewrite

x^{2} + y^{2} + 10 x + 6 y + 18 = 0 x

in the form of the standard circle equation

(x - (- 5))^{2} + (y - (- 3))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 5, - 3), r = 4

x^{2} + y^{2} - 2 x - 6 y = - 6

x^{2} - 4 x + y^{2} + 4 y = - 3

x^{2} + y^{2} + 8 x + 4 y - 4 = 0

X^{2} + Y^{2} - 5 X + 4 Y - 46 = 0

(x - 3)^{2} + (y - (- 2))^{2} = 5^{2}

What is x^2+y^2+10x+6y+18=0x ?
The solution to x^2+y^2+10x+6y+18=0x is Circle with (a,b)=(-5,-3),r=4