What is x^2+y^2-18x+16y+81=0 ?

The solution to x^2+y^2-18x+16y+81=0 is Circle with (a,b)=(9,-8),r=8

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x^2+y^2-18x+16y+81=0

x^{2} + y^{2} - 18 x + 16 y + 81 = 0

(a, b) = (9, - 8), r = 8

Solution steps

x^{2} + y^{2} - 18 x + 16 y + 81 = 0

Rewrite

x^{2} + y^{2} - 18 x + 16 y + 81 = 0

in the form of the standard circle equation

(x - 9)^{2} + (y - (- 8))^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (9, - 8), r = 8

(x + 2)^{2} + y^{2} = 8 y - 7

4 x^{2} + 4 y^{2} + 24 x - 8 y - 41 = 0

x^{2} + y^{2} - 6 x - 12 y + 36 = 0

2 x^{2} + 2 y^{2} + 15 x + 15 y - 15 = 0

(x - 2)^{(2)} + (y + 1)^{(2)} \geq 4

What is x^2+y^2-18x+16y+81=0 ?
The solution to x^2+y^2-18x+16y+81=0 is Circle with (a,b)=(9,-8),r=8