What is (x-15)^2+(y-2)^2=9 ?

The solution to (x-15)^2+(y-2)^2=9 is Circle with (a,b)=(15,2),r=3

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(x-15)^2+(y-2)^2=9

(x - 15)^{2} + (y - 2)^{2} = 9

(a, b) = (15, 2), r = 3

Solution steps

(x - 15)^{2} + (y - 2)^{2} = 9

Rewrite

(x - 15)^{2} + (y - 2)^{2} = 9

in the form of the standard circle equation

(x - 15)^{2} + (y - 2)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (15, 2), r = 3

x^{2} + x + y^{2} + y = 4

(x - 4)^{2} + (y - 3)^{2} = 2 [(x + 2)^{2} + (y - 1)^{2}]

x^{2} + y^{2} + 2 x - 4 y = 11

(x - 37.5)^{2} + (y + 2.5)^{2} = 1^{2}

(y - 2)^{2} + (x - 8)^{2} = 64

What is (x-15)^2+(y-2)^2=9 ?
The solution to (x-15)^2+(y-2)^2=9 is Circle with (a,b)=(15,2),r=3