What is (x-5)^2+(y+7)^2=100 ?

The solution to (x-5)^2+(y+7)^2=100 is Circle with (a,b)=(5,-7),r=10

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(x-5)^2+(y+7)^2=100

(x - 5)^{2} + (y + 7)^{2} = 100

(a, b) = (5, - 7), r = 10

Solution steps

(x - 5)^{2} + (y + 7)^{2} = 100

Rewrite

(x - 5)^{2} + (y + 7)^{2} = 100

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 7))^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (5, - 7), r = 10

x^{2} + y^{2} + 12 x + 6 y + 41 = 0

x^{2} + y^{2} - 10 x + 12 y - 2 = 0

3 x^{2} + 3 y^{2} - 24 x + 12 y - 15 = 0

5 x^{2} + 5 y^{2} - 20 x + 10 y + 21 = 0

x^{2} + y^{2} - 2 x + y - \frac{11}{4} = 0

What is (x-5)^2+(y+7)^2=100 ?
The solution to (x-5)^2+(y+7)^2=100 is Circle with (a,b)=(5,-7),r=10