What is x^2+y^2-2x-1y-49=0 ?

The solution to x^2+y^2-2x-1y-49=0 is Circle with (a,b)=(1, 1/2),r=(sqrt(201))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-2x-1y-49=0

x^{2} + y^{2} - 2 x - 1 y - 49 = 0

(a, b) = (1, \frac{1}{2}), r = \frac{201}{2}

Solution steps

x^{2} + y^{2} - 2 x - 1 \cdot y - 49 = 0

Rewrite

x^{2} + y^{2} - 2 x - 1 y - 49 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - \frac{1}{2})^{2} = (\frac{201}{2})^{2}

Therefore the circle properties are:

(a, b) = (1, \frac{1}{2}), r = \frac{201}{2}

x^{2} + 10 x + y^{2} = 0

x^{2} + 2 x + y^{2} - 18 y = - 57

(x + 4)^{2} + (y + 3)^{2} = 9

(x - 1)^{2} + (y - 2)^{2} = 123.21

x^{2} + y^{2} - 25 x - 25 y + 100 = 0

What is x^2+y^2-2x-1y-49=0 ?
The solution to x^2+y^2-2x-1y-49=0 is Circle with (a,b)=(1, 1/2),r=(sqrt(201))/2