What is x^2+y^2+5x-7y-18=0 ?

The solution to x^2+y^2+5x-7y-18=0 is Circle with (a,b)=(-5/2 , 7/2),r=sqrt(73/2)

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x^2+y^2+5x-7y-18=0

x^{2} + y^{2} + 5 x - 7 y - 18 = 0

(a, b) = (- \frac{5}{2}, \frac{7}{2}), r = \frac{73}{2}

Solution steps

x^{2} + y^{2} + 5 x - 7 y - 18 = 0

Rewrite

x^{2} + y^{2} + 5 x - 7 y - 18 = 0

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - \frac{7}{2})^{2} = (\frac{73}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, \frac{7}{2}), r = \frac{73}{2}

x^{2} + (y - 10)^{2} = 225

2 x^{2} - 6 x + 2 y^{2} + 2 y - 45 = 0

(x + 2)^{2} + (y - 5)^{2} = 1

(x - 1)^{2} + (y + 3)^{2} = 4^{2}

(x + 1)^{2} + (y - 1)^{2} = 6^{2}

What is x^2+y^2+5x-7y-18=0 ?
The solution to x^2+y^2+5x-7y-18=0 is Circle with (a,b)=(-5/2 , 7/2),r=sqrt(73/2)