What is the center x^2+y^2-2x-6y-6=0 ?

The center x^2+y^2-2x-6y-6=0 is (1,3)

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center x^2+y^2-2x-6y-6=0

center

x^{2} + y^{2} - 2 x - 6 y - 6 = 0

(1, 3)

Solution steps

x^{2} + y^{2} - 2 x - 6 y - 6 = 0

Rewrite

x^{2} + y^{2} - 2 x - 6 y - 6 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 3)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, 3), r = 4

And the center is:

(1, 3)

x^{2} + y^{2} = 49

x^{2} + y^{2} = 4

x^{2} + y^{2} = 25

x^{2} + y^{2} - 5 x + 4 y = 46

x^{2} + y^{2} - 16 = 0