What is the center x^2+y^2-6x+8y=144 ?

The center x^2+y^2-6x+8y=144 is (3,-4)

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center x^2+y^2-6x+8y=144

center

x^{2} + y^{2} - 6 x + 8 y = 144

(3, - 4)

Solution steps

x^{2} + y^{2} - 6 x + 8 y = 144

Rewrite

x^{2} + y^{2} - 6 x + 8 y = 144

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 4))^{2} = 1 3^{2}

Therefore the circle properties are:

(a, b) = (3, - 4), r = 13

And the center is:

(3, - 4)

x^{2} + y^{2} - 2 x + 4 y + 1 = 0

x^{2} + y^{2} + 6 x - 4 y - 23 = 0

5 x^{2} + 5 y^{2} = 125

x^{2} + y^{2} - 4 x - 4 y = 0

x^{2} + y^{2} - 12 x + 20 y + 15 = 0