What is the center x^2+y^2-2x+6y+9=0 ?

The center x^2+y^2-2x+6y+9=0 is (1,-3)

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center x^2+y^2-2x+6y+9=0

center

x^{2} + y^{2} - 2 x + 6 y + 9 = 0

(1, - 3)

Solution steps

x^{2} + y^{2} - 2 x + 6 y + 9 = 0

Rewrite

x^{2} + y^{2} - 2 x + 6 y + 9 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 3))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (1, - 3), r = 1

And the center is:

(1, - 3)

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