What is the center x^2+y^2-14x+2y=-14 ?

The center x^2+y^2-14x+2y=-14 is (7,-1)

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center x^2+y^2-14x+2y=-14

center

x^{2} + y^{2} - 14 x + 2 y = - 14

(7, - 1)

Solution steps

x^{2} + y^{2} - 14 x + 2 y = - 14

Rewrite

x^{2} + y^{2} - 14 x + 2 y = - 14

in the form of the standard circle equation

(x - 7)^{2} + (y - (- 1))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (7, - 1), r = 6

And the center is:

(7, - 1)

4 x^{2} + 4 y^{2} - 16 x + 40 y + 67 = 0

x^{2} + (y - 3)^{2} = 36

(x - \frac{7}{4})^{2} + (y + \frac{3}{4})^{2} = \frac{169}{16}

x^{2} + y^{2} + 8 x - 2 y - 19 = 0

2 x^{2} + 2 y^{2} - 14 x + 18 y = 7