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Popular >

center x^2+y^2=5

Solution

center

x^{2} + y^{2} = 5

Solution

(0, 0)

Solution steps

x^{2} + y^{2} = 5

Rewrite

x^{2} + y^{2} = 5

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 5

And the center is:

(0, 0)

Popular Examples

center x^2+y^2-4x=5 center

x^{2} + y^{2} - 4 x = 5

center 2x^2-6x+2y^2+2y=45 center

2 x^{2} - 6 x + 2 y^{2} + 2 y = 45

center x^2+y^2-2x-6y-15=0 center

x^{2} + y^{2} - 2 x - 6 y - 15 = 0

center x^2+24x+y^2+10y=-160 center

x^{2} + 24 x + y^{2} + 10 y = - 160

center (x+2)^2+(y-3)^2=16 center

(x + 2)^{2} + (y - 3)^{2} = 16

Frequently Asked Questions (FAQ)

What is the center x^2+y^2=5 ?
The center x^2+y^2=5 is (0,0)