What is the center x^2+y^2+2x+18y-143=0 ?

The center x^2+y^2+2x+18y-143=0 is (-1,-9)

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center x^2+y^2+2x+18y-143=0

center

x^{2} + y^{2} + 2 x + 18 y - 143 = 0

(- 1, - 9)

Solution steps

x^{2} + y^{2} + 2 x + 18 y - 143 = 0

Rewrite

x^{2} + y^{2} + 2 x + 18 y - 143 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 9))^{2} = 1 5^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 9), r = 15

And the center is:

(- 1, - 9)

x^{2} + y^{2} - 2 x - 4 y + 1 = 0

x^{2} + y^{2} - 2 x - 15 = 0

4 x^{2} + 4 y^{2} - 16 x + 24 y - 12 = 0

x^{2} + 10 x + y^{2} - 16 y - 11 = 0

2 x^{2} + 2 y^{2} - 2 x - 2 y - 3 = 0

What is the center x^2+y^2+2x+18y-143=0 ?
The center x^2+y^2+2x+18y-143=0 is (-1,-9)