What is the center x^2+y^2-14x+12y=36 ?

The center x^2+y^2-14x+12y=36 is (7,-6)

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center x^2+y^2-14x+12y=36

center

x^{2} + y^{2} - 14 x + 12 y = 36

(7, - 6)

Solution steps

x^{2} + y^{2} - 14 x + 12 y = 36

Rewrite

x^{2} + y^{2} - 14 x + 12 y = 36

in the form of the standard circle equation

(x - 7)^{2} + (y - (- 6))^{2} = 1 1^{2}

Therefore the circle properties are:

(a, b) = (7, - 6), r = 11

And the center is:

(7, - 6)

(x + 3)^{2} + (y - 5)^{2} = 5

x^{2} + y^{2} + 2 x - 2 y = 3

x^{2} + y^{2} + 4 x + 20 y + 23 = 0

2 x^{2} + 2 y^{2} - 8 x + 16 y - 32 = 0

(x - 3)^{2} + (y + 5)^{2} = 16