What is the center 4x^2+4y^2=100 ?

The center 4x^2+4y^2=100 is (0,0)

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center 4x^2+4y^2=100

center

4 x^{2} + 4 y^{2} = 100

(0, 0)

Solution steps

4 x^{2} + 4 y^{2} = 100

Rewrite

4 x^{2} + 4 y^{2} = 100

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 5

And the center is:

(0, 0)

(x - 2)^{2} + (y + 1)^{2} = 9

x^{2} + y^{2} - 2 x - 8 y - 19 = 0

x^{2} + y^{2} + 2 x - 4 y - 15 = 0

x^{2} + y^{2} = a^{2}

(x + 2)^{2} + y^{2} = 9