What is the center (x-(-5))^2+(y-7)^2=sqrt(11) ?

The center (x-(-5))^2+(y-7)^2=sqrt(11) is (-5,7)

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center (x-(-5))^2+(y-7)^2=sqrt(11)

center

(x - (- 5))^{2} + (y - 7)^{2} = 11

(- 5, 7)

Solution steps

(x - (- 5))^{2} + (y - 7)^{2} = 11

Rewrite

(x - (- 5))^{2} + (y - 7)^{2} = 11

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 7)^{2} = (11)^{2}

Therefore the circle properties are:

(a, b) = (- 5, 7), r = 11

And the center is:

(- 5, 7)

x^{2} + y^{2} - 6 x - 10 y + 2 = 0

x^{2} + y^{2} - 2 x - 4 y - 4 = 0

4 x^{2} + 4 y^{2} + 12 x + 16 y - 11 = 0

(x + 2)^{2} + (y - 3)^{2} = 25

x^{2} + y^{2} + 2 x = 3 y

What is the center (x-(-5))^2+(y-7)^2=sqrt(11) ?
The center (x-(-5))^2+(y-7)^2=sqrt(11) is (-5,7)