What is the center (x-5)^2+(y-3)^2=49 ?

The center (x-5)^2+(y-3)^2=49 is (5,3)

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center (x-5)^2+(y-3)^2=49

center

(x - 5)^{2} + (y - 3)^{2} = 49

(5, 3)

Solution steps

(x - 5)^{2} + (y - 3)^{2} = 49

Rewrite

(x - 5)^{2} + (y - 3)^{2} = 49

in the form of the standard circle equation

(x - 5)^{2} + (y - 3)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (5, 3), r = 7

And the center is:

(5, 3)

y^{2} + x^{2} + 24 x + 10 y + 160 = 0

(x + 2)^{2} + (y + 3)^{2} = 9

(x + 2)^{2} + (y - 5)^{2} = 4

y^{2} + 4 x - 20 - 2 y = - x^{2}

(x - 1)^{2} + (y - 3)^{2} = 16