Solution

center

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:

Popular Examples

center y^2+x^2<= 4center center x^2-9=-y^2center center x^2+y^2-8x-14y-16=0center center (x-3)^2+(y+2)^2=29center center (x-3)^2+(y+2)^2=25center

Frequently Asked Questions (FAQ)

  • What is the center x^2+y^2-4x-8y-16=0 ?

    The center x^2+y^2-4x-8y-16=0 is (2,4)