What is -f(x)=4x^2+3x-4 ?

The solution to -f(x)=4x^2+3x-4 is Parabola with (h,k)=(-3/8 , 73/16),p=-1/16

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-f(x)=4x^2+3x-4

- f (x) = 4 x^{2} + 3 x - 4

(h, k) = (- \frac{3}{8}, \frac{73}{16}), p = - \frac{1}{16}

Solution steps

- y = 4 x^{2} + 3 x - 4

Rewrite

- y = 4 x^{2} + 3 x - 4

in the standard form

4 (- \frac{1}{16}) (y - \frac{73}{16}) = (x - (- \frac{3}{8}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{8}, \frac{73}{16}), p = - \frac{1}{16}

x^{2} - 6 x - 4 y - 11 = 0

- f (x) = 2 x^{2} - 3 x + 4

x = 0.45 - 500 (0.03 - y)^{2}

x - y^{2} = 2

(x - 1)^{2} = 16 (y - 2)

What is -f(x)=4x^2+3x-4 ?
The solution to -f(x)=4x^2+3x-4 is Parabola with (h,k)=(-3/8 , 73/16),p=-1/16