Solution

center

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:

Popular Examples

center x^2+(y+2)^2=4center center x^2+y^2-8x-2y-19=0center center (x-5)^2+(y+2)^2=16center center 2x^2+2y^2+16x+20y+18=0center center 2x^2+2y^2-12x+4y-12=0center

Frequently Asked Questions (FAQ)

  • What is the center x^2+y^2+6y+4x+8=0 ?

    The center x^2+y^2+6y+4x+8=0 is (-2,-3)