What is the center 4x^2+4y^2=144 ?

The center 4x^2+4y^2=144 is (0,0)

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center 4x^2+4y^2=144

center

4 x^{2} + 4 y^{2} = 144

(0, 0)

Solution steps

4 x^{2} + 4 y^{2} = 144

Rewrite

4 x^{2} + 4 y^{2} = 144

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 6

And the center is:

(0, 0)

(x + 1)^{2} + y^{2} = 246

(x - 4)^{2} + (y + 1^{2})^{2} = 9

(x + \frac{9}{4})^{2} = \frac{13}{2} - (y - 8)^{2}

x^{2} + y^{2} + 12 x + 8 y + 3 = 0

(x + 4)^{2} + (y - 5)^{2} = 25