Solution

center

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:

Popular Examples

center 2x^2+2y^2+8x+7=0center center (x-2)^2+(y-3)^2=58center center (x-2)^2+y^2=6center center x^2+y^2=144center center (x+2)^2+y^2=4center

Frequently Asked Questions (FAQ)

  • What is the center x^2+y^2+2y-16=0 ?

    The center x^2+y^2+2y-16=0 is (0,-1)