What is the center (y+8)^2+(x+2)^2=72 ?

The center (y+8)^2+(x+2)^2=72 is (-2,-8)

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center (y+8)^2+(x+2)^2=72

center

(y + 8)^{2} + (x + 2)^{2} = 72

(- 2, - 8)

Solution steps

(y + 8)^{2} + (x + 2)^{2} = 72

Rewrite

(y + 8)^{2} + (x + 2)^{2} = 72

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 8))^{2} = (72)^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 8), r = 72

And the center is:

(- 2, - 8)

(x - 3)^{2} + (y - (- 2))^{2} = 35

(x + 5)^{2} + (y + 6)^{2} = \frac{2}{3}

x^{2} + 5 x + y^{2} - y = \frac{5}{2}

(x - 4)^{2} + (y + 1)^{2} = 18

(x - 4)^{2} + (y + 1)^{2} = 16

What is the center (y+8)^2+(x+2)^2=72 ?
The center (y+8)^2+(x+2)^2=72 is (-2,-8)