What is the center (x-17)^2+(y+5)^2=144 ?

The center (x-17)^2+(y+5)^2=144 is (17,-5)

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center (x-17)^2+(y+5)^2=144

center

(x - 17)^{2} + (y + 5)^{2} = 144

(17, - 5)

Solution steps

(x - 17)^{2} + (y + 5)^{2} = 144

Rewrite

(x - 17)^{2} + (y + 5)^{2} = 144

in the form of the standard circle equation

(x - 17)^{2} + (y - (- 5))^{2} = 1 2^{2}

Therefore the circle properties are:

(a, b) = (17, - 5), r = 12

And the center is:

(17, - 5)

(x + 5)^{2} + (y + 5)^{2} = 64

2 x^{2} + 2 y^{2} - 4 x + 12 y - 18 = 0

x^{2} + y^{2} + 2 x - 6 y + 6 = 0

x^{2} + y^{2} + 6 x - 10 y + 18 = 0

x^{2} + 6 x + y^{2} = 7

What is the center (x-17)^2+(y+5)^2=144 ?
The center (x-17)^2+(y+5)^2=144 is (17,-5)