What is the center ((x+7)^2)/(16)+((y+5)^2)/(16)=1 ?

The center ((x+7)^2)/(16)+((y+5)^2)/(16)=1 is (-7,-5)

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center ((x+7)^2)/(16)+((y+5)^2)/(16)=1

center

\frac{( x + 7 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

(- 7, - 5)

Solution steps

\frac{( x + 7 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

Rewrite

\frac{( x + 7 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

in the form of the standard circle equation

(x - (- 7))^{2} + (y - (- 5))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 7, - 5), r = 4

And the center is:

(- 7, - 5)

x^{2} + 4 x + y^{2} + 6 y + 9 = 0

(x - 2)^{2} + (y + 6)^{2} = 25

(x - 1)^{2} + y^{2} = 4

(x - 2)^{2} + (y + 3)^{2} = 16

(x - 2)^{2} + (y + 4)^{2} - 16 = 0

What is the center ((x+7)^2)/(16)+((y+5)^2)/(16)=1 ?
The center ((x+7)^2)/(16)+((y+5)^2)/(16)=1 is (-7,-5)