What is the center x^2+(y-1)^2=49 ?

The center x^2+(y-1)^2=49 is (0,1)

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center x^2+(y-1)^2=49

center

x^{2} + (y - 1)^{2} = 49

(0, 1)

Solution steps

x^{2} + (y - 1)^{2} = 49

Rewrite

x^{2} + (y - 1)^{2} = 49

in the form of the standard circle equation

(x - 0)^{2} + (y - 1)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (0, 1), r = 7

And the center is:

(0, 1)

3 x^{2} + 3 y^{2} - 18 x - 18 y + 42 = 0

(x - 4)^{2} + (y - 1)^{2} = 64

x^{2} + y^{2} - 6 x + 7 y - 16 = 0

(x - 5)^{2} + (y - 1)^{2} = 49

x^{2} + (y - 1)^{2} = 36