What is the center (X-5)^2+(Y-6)^2=36 ?

The center (X-5)^2+(Y-6)^2=36 is (5,6)

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center (X-5)^2+(Y-6)^2=36

center

(X - 5)^{2} + (Y - 6)^{2} = 36

(5, 6)

Solution steps

(X - 5)^{2} + (Y - 6)^{2} = 36

Rewrite

(X - 5)^{2} + (Y - 6)^{2} = 36

in the form of the standard circle equation

(X - 5)^{2} + (Y - 6)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (5, 6), r = 6

And the center is:

(5, 6)

(x + 3)^{2} + y^{2} = 48

x^{2} + y^{2} + 2 x - \frac{27}{2} y + 20 = 0

x^{2} + (y - 2)^{2} = 1

x^{2} + y^{2} - 12 x - 12 y + 36 = 0

(x - 3)^{2} + (y + 9)^{2} = 9^{2}