What is the radius 2x^2+2y^2-12x+8y-24=0 ?

The radius 2x^2+2y^2-12x+8y-24=0 is r=5

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radius 2x^2+2y^2-12x+8y-24=0

radius

2 x^{2} + 2 y^{2} - 12 x + 8 y - 24 = 0

r = 5

Solution steps

2 x^{2} + 2 y^{2} - 12 x + 8 y - 24 = 0

Rewrite

2 x^{2} + 2 y^{2} - 12 x + 8 y - 24 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 2))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (3, - 2), r = 5

And the radius is:

r = 5

x^{2} + y^{2} - 5 x + 4 y = 46

x^{2} + y^{2} = 16

x^{2} + y^{2} = 49

(x - 6)^{2} + (y - 4)^{2} - 64 = 0

x^{2} + y^{2} + 12 x - 4 y - 40 = 0

What is the radius 2x^2+2y^2-12x+8y-24=0 ?
The radius 2x^2+2y^2-12x+8y-24=0 is r=5