What is the radius x^2+y^2+14x-2y+25=0 ?

The radius x^2+y^2+14x-2y+25=0 is r=5

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radius x^2+y^2+14x-2y+25=0

radius

x^{2} + y^{2} + 14 x - 2 y + 25 = 0

r = 5

Solution steps

x^{2} + y^{2} + 14 x - 2 y + 25 = 0

Rewrite

x^{2} + y^{2} + 14 x - 2 y + 25 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 1)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 7, 1), r = 5

And the radius is:

r = 5

x^{2} + y^{2} - 12 x + 20 y + 15 = 0

16 x^{2} + 16 y^{2} + 8 x - 32 y = - 1

x^{2} + y^{2} - 2 x + 6 y - 15 = 0

2 x^{2} + 2 y^{2} - 14 x + 18 y = 7

x^{2} = 16 - y^{2}