What is the radius 36x^2+36y^2-12x-27y-8=0 ?

The radius 36x^2+36y^2-12x-27y-8=0 is r= 5/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius 36x^2+36y^2-12x-27y-8=0

radius

36 x^{2} + 36 y^{2} - 12 x - 27 y - 8 = 0

r = \frac{5}{8}

Solution steps

36 x^{2} + 36 y^{2} - 12 x - 27 y - 8 = 0

Rewrite

36 x^{2} + 36 y^{2} - 12 x - 27 y - 8 = 0

in the form of the standard circle equation

(x - \frac{1}{6})^{2} + (y - \frac{3}{8})^{2} = (\frac{5}{8})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{6}, \frac{3}{8}), r = \frac{5}{8}

And the radius is:

r = \frac{5}{8}

x^{2} + y^{2} = 72

x^{2} + y^{2} = 10

5 x^{2} + 5 y^{2} = 125

3 (x - 2)^{2} + 3 y^{2} = 3

x^{2} + y^{2} - 14 x + 2 y + 41 = 0

What is the radius 36x^2+36y^2-12x-27y-8=0 ?
The radius 36x^2+36y^2-12x-27y-8=0 is r= 5/8