What is the radius x^2+(y-3)^2=36 ?

The radius x^2+(y-3)^2=36 is r=6

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radius x^2+(y-3)^2=36

radius

x^{2} + (y - 3)^{2} = 36

r = 6

Solution steps

x^{2} + (y - 3)^{2} = 36

Rewrite

x^{2} + (y - 3)^{2} = 36

in the form of the standard circle equation

(x - 0)^{2} + (y - 3)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (0, 3), r = 6

And the radius is:

r = 6

x^{2} + y^{2} = \frac{1}{4}

x^{2} + y^{2} - 8 x + 12 y = - 43

x^{2} + y^{2} + 4 x - 2 y = - 1

x^{2} + y^{2} = 12

8 x^{2} + 8 y^{2} - 20 x + 64 y - 371 = 0