What is the radius x^2-14x+y^2+6y+9=0 ?

The radius x^2-14x+y^2+6y+9=0 is r=7

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radius x^2-14x+y^2+6y+9=0

radius

x^{2} - 14 x + y^{2} + 6 y + 9 = 0

r = 7

Solution steps

x^{2} - 14 x + y^{2} + 6 y + 9 = 0

Rewrite

x^{2} - 14 x + y^{2} + 6 y + 9 = 0

in the form of the standard circle equation

(x - 7)^{2} + (y - (- 3))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (7, - 3), r = 7

And the radius is:

r = 7

x^{2} + y^{2} - 8 x + 2 y + 8 = 0

x^{2} + y^{2} - 14 x + 12 y = 36

x^{2} + y^{2} + 8 y - 48 = 0

(x + 5)^{2} + (y + 1)^{2} = 9

x^{2} + y^{2} = 2 x