What is the radius (x-1)^2+(y+3)^2=4 ?

The radius (x-1)^2+(y+3)^2=4 is r=2

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radius (x-1)^2+(y+3)^2=4

radius

(x - 1)^{2} + (y + 3)^{2} = 4

r = 2

Solution steps

(x - 1)^{2} + (y + 3)^{2} = 4

Rewrite

(x - 1)^{2} + (y + 3)^{2} = 4

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 3))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (1, - 3), r = 2

And the radius is:

r = 2

x^{2} + y^{2} - 6 x - 8 y - 11 = 0

x^{2} - 10 x + y^{2} + 2 y + 10 = 0

x^{2} - 4 x + y^{2} + 8 y = - 4

(x + 5)^{2} + (y + 4)^{2} = 9

(x - 3)^{2} + (y + 1)^{2} = 16