What is the radius x^2+y^2-7x=36-4y ?

The radius x^2+y^2-7x=36-4y is r=(sqrt(209))/2

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radius x^2+y^2-7x=36-4y

radius

x^{2} + y^{2} - 7 x = 36 - 4 y

r = \frac{209}{2}

Solution steps

x^{2} + y^{2} - 7 x = 36 - 4 y

Rewrite

x^{2} + y^{2} - 7 x = 36 - 4 y

in the form of the standard circle equation

(x - \frac{7}{2})^{2} + (y - (- 2))^{2} = (\frac{209}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{7}{2}, - 2), r = \frac{209}{2}

And the radius is:

r = \frac{209}{2}

(x - 5)^{2} + (y + 1)^{2} = 16

(x - 3)^{2} + (y + 4)^{2} = 16

x^{2} + y^{2} + 4 x + 20 y + 23 = 0

2 x^{2} + 2 y^{2} - 3 x = 0

x^{2} - 8 x + y^{2} - 10 y = 40

What is the radius x^2+y^2-7x=36-4y ?
The radius x^2+y^2-7x=36-4y is r=(sqrt(209))/2