What is the radius 2x^2+2y^2+10x-6y-55=0 ?

The radius 2x^2+2y^2+10x-6y-55=0 is r=6

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radius 2x^2+2y^2+10x-6y-55=0

radius

2 x^{2} + 2 y^{2} + 10 x - 6 y - 55 = 0

r = 6

Solution steps

2 x^{2} + 2 y^{2} + 10 x - 6 y - 55 = 0

Rewrite

2 x^{2} + 2 y^{2} + 10 x - 6 y - 55 = 0

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - \frac{3}{2})^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, \frac{3}{2}), r = 6

And the radius is:

r = 6

x^{2} - 6 x + 9 + y^{2} - 4 y + 4 = 16

x^{2} + y^{2} - 4 x + 6 y - 3 = 0

x^{2} + y^{2} + 6 x - 2 y - 15 = 0

(x - 0)^{2} + (y - 0)^{2} = 4

(x + \frac{1}{2})^{2} + (y - \frac{4}{5})^{2} = \frac{9}{4}

What is the radius 2x^2+2y^2+10x-6y-55=0 ?
The radius 2x^2+2y^2+10x-6y-55=0 is r=6