What is the radius x^2+(y-5)^2=25 ?

The radius x^2+(y-5)^2=25 is r=5

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radius x^2+(y-5)^2=25

radius

x^{2} + (y - 5)^{2} = 25

r = 5

Solution steps

x^{2} + (y - 5)^{2} = 25

Rewrite

x^{2} + (y - 5)^{2} = 25

in the form of the standard circle equation

(x - 0)^{2} + (y - 5)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (0, 5), r = 5

And the radius is:

r = 5

x^{2} + y^{2} - 2 y - 8 = 0

(x + 3)^{2} + (y - 3)^{2} = 8

(x - \frac{3}{2})^{2} + y^{2} = \frac{9}{4}

x^{2} + y^{2} + 14 x + 12 y + 21 = 0

3.5 (x + 2.2)^{2} + 3.5 (y - 11.1)^{2} - 21 = 0