What is the radius x^2+y^2+6x-2y+1=0 ?

The radius x^2+y^2+6x-2y+1=0 is r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius x^2+y^2+6x-2y+1=0

radius

x^{2} + y^{2} + 6 x - 2 y + 1 = 0

r = 3

Solution steps

x^{2} + y^{2} + 6 x - 2 y + 1 = 0

Rewrite

x^{2} + y^{2} + 6 x - 2 y + 1 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 1)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 3, 1), r = 3

And the radius is:

r = 3

x^{2} + y^{2} + 10 x + 12 y + 25 = 0

x^{2} + y^{2} - 10 x - 8 y = - 5

x^{2} - 2 x + y^{2} - 8 y + 1 = 0

x^{2} + y^{2} - 8 x + 12 y + 10 = 0

x^{2} + y^{2} - 4 x + 8 y + 5 = 0